The block slips and slides on the slanted face of the wedge.
The slanted face of the wedge can be described as a straight line
y = - x + At2/2
with slope -1, and with an intercept that depends on time.
Then take the second derivative in time to get
d2y/dt2 = - d2x/dt2 + A
so that the components of the block's acceleration are related by
ay = - ax + A
You should now be able to simultaneously solve this equation
together with the two components of Newton's 2nd law for the block
F=ma
where as usual, the total force on the block is the sum of gravity and an unknown normal force from the wedge.